Answer:
\[A=2+4x+8{{x}^{2}}\] \[B=-3-5x+{{x}^{2}}\] \[C=1+3x-7{{x}^{2}}\] A+B+C=? A+B+C=\[\left( 2+4x+8{{x}^{2}} \right)+\left( -3-5x+{{x}^{2}} \right)\] \[+\left( 1+3x-7{{x}^{2}} \right)\] \[=2+4x+8{{x}^{2}}-3-5x+{{x}^{2}}+1+3x-7{{x}^{2}}\] \[={{x}^{2}}+1-7)4-x(4-5+3)+2-3+1\] \[=\text{ }2{{x}^{2}}+2x+0\] = \[2{{x}^{2}}\]+2x = 2x(x + 1).
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