question_answer

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach - 350 m.

Answer:

Difference in heights at two position = 10 m - (-350 m) = 360 m Rate of descent = 6 m/minute \[\therefore \]            Time taken = \[\left( 360\div 6 \right)\] minutes = 60 minutes i.e., one hour.