Answer:
Sum of digits of odd place = 7 + 6 = 13 Sum of digit of even place = 5 + x Difference \[\left( x+5 \right)-13=\text{ }x-8~\] (i) Now \[\left( x-8 \right)\]should be equal 0 or a multiple of 11 (i.e., 11, 22, 33,... etc) \[x-8=0\] \[\Rightarrow \] \[x=8\text{ }or\text{ }x-8=11\] x = 11 + 8 = 19 Since, x is a digit, so it can take value from 0-9 Hence, x = 8 Required number is 7568.
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