Answer:
\[(-3{{x}^{2}}y)\times (4{{x}^{2}}y-3x{{y}^{2}}+4x-5y)=-12{{x}^{4}}{{y}^{2}}+9{{x}^{3}}{{y}^{3}}-12{{x}^{3}}y+15{{x}^{2}}{{y}^{2}}\]
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