Answer:
Since, \[\frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}\] \[\therefore \frac{5\left( 2x-1 \right)}{3\times 5}-\frac{3\left( 6x-2 \right)}{5\times 3}=\frac{1}{3}\] \[\frac{10x-5}{15}-\frac{\left( 18x-6 \right)}{15}=\frac{1}{3}\] \[\frac{10x-5-18x+6}{15}=\frac{1}{3}\] \[\frac{-8x+1}{15}-\frac{1}{3}\] \[-8x+1=\frac{15}{3}\]=5 \[-8x=5-1=4\] \[x=\frac{4}{-8}\] Thus, \[x=\frac{-2}{9}\]
You need to login to perform this action.
You will be redirected in
3 sec
