question_answer

Find the area of quadrilateral ABCD as shown in the figure.

Answer:

Quadrilateral is divided into triangle.

Here, \[{{h}_{1}}=13\text{ }m,\text{ }{{h}_{2}}=8\text{ }m\] and AC = 24 m

Area of quadrilateral ABCD

= Area of \[\Delta ADC\]+ Area of \[\Delta ABC\]

\[=\frac{1}{2}\times b\times {{h}_{1}}+\frac{1}{2}\times b\times {{h}_{2}}\]

\[=\frac{1}{2}\times 24\times 13+\frac{1}{2}\times 24\times 8\]

\[=12\times 13+12\times 8\]

= 156 + 96

\[=\text{ }252\text{ }{{m}^{2}}\]

The area of quadrilateral field\[=\text{ }252\text{ }{{m}^{2}}\].