question_answer

If two angles of a triangle are equal and third angle is of\[110{}^\circ \]. Find the equal angles-

Answer:

Let the equal angles be x \[x+x+110{}^\circ =180{}^\circ \](By angle sum property) \[2x\text{ }+\text{ }110{}^\circ \text{ }-\text{ }180{}^\circ \] \[2x-180{}^\circ -110{}^\circ \] \[2x-70{}^\circ \]  \[x=\frac{{{70}^{\circ }}}{2}\] x = \[35{}^\circ \] Hence, equal angles are of\[35{}^\circ \].