Answer:
Let the other side be x metres. Since ΔABC is a right triangle. Therefore, \[A{{C}^{2}}=A{{D}^{2}}+C{{D}^{2}}\] \[{{50}^{2}}={{48}^{2}}+{{x}^{2}}\] \[{{x}^{2}}={{\left( 50 \right)}^{2}}{{\left( 48 \right)}^{2}}\] \[{{x}^{2}}=\left( 50+48 \right)\left( 5048 \right)\] \[{{x}^{2}}=98\times 2\] \[{{x}^{2}}={{14}^{2}}\] x = 14 Thus, the other side of the rectangle is 14 m. ∴ Area of the rectangle\[~=(48\times 14){{m}^{2}}=672{{m}^{2}}\]
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