Answer:
By Phythagoras theorem, 
\[{{\left( 3x \right)}^{2}}+{{\left( 4x \right)}^{2}}={{\left( AC \right)}^{2}}\] \[AC=\sqrt{\text{ }9{{x}^{2}}+16{{x}^{2}}}\] \[=\sqrt{25{{x}^{2}}}=5x\] AC = 5x
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