• # question_answer The side of a square is 5 cm. How many times does the area increase, if the side of the square is doubled?

Given,   side of square = 5 cm $\therefore$      Area of square $=side\times side$            $=5\times 5$            $=25\text{ }sq\text{ }cm$                                                                                                            Now according to question, New side $=2\times$initial side   $=2\times 5$    $=10\text{ }cm$                                                                                                                      $\therefore$ Area of new square $=side\times side$           $=10\times 10$            $=100\text{ }sq\text{ }cm$.                                                                                                       $\therefore$ $\frac{\text{Area}\,\,\text{of}\,\,\text{new}\,\,\text{square}}{\text{Area}\,\,\text{of}\,\,\text{old}\,\,\text{square}}=\frac{100}{25}=4$ Hence, the area of new square is 4 times increase.

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