Answer:
Since, \[3\left( \text{ }x+\frac{1}{2} \right)=18\] Dividing both sides by 3, we get \[x+\frac{1}{2}=\frac{18}{3}\] \[x+\frac{1}{2}=6\] \[x=6-\frac{1}{2}\] [On transposing \[\frac{1}{2}\] to RHS] \[x=\frac{12-1}{2}=\frac{11}{2}\]
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