When a = 0, b = -1, find the value of the given expressions: |
(a) 2a+2b |
(b) \[2{{a}^{2}}+\text{ }b2\text{ }+\text{ }1\] |
(c) \[2{{a}^{2}}b+2a{{b}^{2}}+ab\] |
Answer:
When a = 0, b = -1 then, (a) 2a + 2b - 0 + 2(-1) = - 2 (b) \[2{{a}^{2}}+{{b}^{2}}+1-0+{{\left( -1 \right)}^{2}}+1=1+1=2\] (c)\[2{{a}^{2}}b+2a{{b}^{2}}+ab=0+0+0=0\]
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