question_answer

Factorise 14pq + 35pqr.

Answer:

\[14pq+35pqr\]

\[14pq=2\times 7\times p\times q\]

\[35pqr=5\times 7\times p\times q\times r\]

The common factor of the three terms are 7, p and q.

Therefore,

\[14pq+35pqr=\left( 2\times 7\times p\times q \right)+\left( 5\times 7\times p\times q\times r \right)\]

\[=7\times p\times q\left( 2+5r \right)\]

\[=7pq\left( 2+5r \right)~~\]