question_answer

Find:

(a) \[\frac{7}{48}-\frac{17}{36}\]

(b) \[\frac{5}{63}-\left( \frac{-6}{21} \right)\]

(c) \[\frac{-6}{13}-\left( \frac{-7}{15} \right)\]

(d) \[\frac{-3}{8}-\frac{7}{11}\]

Answer:

(a)\[\frac{7}{48}-\frac{17}{36}=\frac{7(3)-17(4)}{144}\]

=\[\frac{21-68}{144}\]

\[=\frac{-47}{144}\]

(b) \[\frac{5}{36}-\left( \frac{-6}{21} \right)=\frac{5}{63}+\frac{6}{21}\]

\[=\frac{5+6\left( 3 \right)}{63}\]

\[=\frac{5+18}{63}=\frac{23}{63}\]

(c) \[\frac{-6}{13}-\left( \frac{-7}{15} \right)=\frac{-6}{13}-\frac{7}{15}\]

\[=\frac{-6(15)+7(13)}{195}\]

\[=\frac{-90+91}{195}=\frac{1}{195}\]

(d) \[\frac{-3}{8}-\frac{7}{11}~\frac{-3\left( 11 \right)-7\left( 8 \right)}{88}\]

\[=\frac{-33-56}{88}=\frac{-89}{88}.\]

\[=-1\frac{1}{88}.\]