question_answer

Solve the following equations:

(a) \[2y+\frac{5}{2}=\frac{37}{2}\]

(b) 5t + 28 = 10

(C) \[\frac{a}{5}+3=2\]

(d) \[\frac{q}{4}+7=5\]

Answer:

(a) \[2y+\frac{5}{2}=\frac{37}{2}\]

\[2y=\frac{37}{2}-\frac{5}{2}\]

\[2y=\frac{32}{2}\]

2y = 16

\[y=\frac{16}{2}\]

\[\therefore \]      y = 8

(b)   5t + 28 = 10

5t = 10 - 28

5t = -18

\[\therefore \] \[t=-\frac{18}{5}\]

(c)   \[~\frac{a}{5}+3=2\]

\[~\frac{a}{5}=2-3\]

\[~\frac{a}{5}=-1\]

\[a=-1\times 5\]

\[\therefore \]      A = - 5

(d) \[\frac{q}{4}+7=5\]

\[\frac{q}{4}=5-7\]

\[\frac{q}{4}=-2\]

\[q=-2\times 4\]

\[\therefore \] \[q=-8\]