• # question_answer If the point of intersection of the $\frac{{{x}^{2}}}{{{a}^{2}}}\,+\,\frac{{{y}^{2}}}{{{b}^{2}}}\,=\,1$ and $\frac{{{x}^{2}}}{{{\alpha }^{2}}}+\frac{{{y}^{2}}}{{{\beta }^{2}}}=1$ are at the extremities of the conjugate diameters of the former, then ______.      A)  $\frac{{{a}^{2}}}{{{\alpha }^{2}}}+\frac{{{b}^{2}}}{{{\beta }^{2}}}=2$                      B)  $\frac{{{\alpha }^{2}}}{{{a}^{2}}}-\frac{{{\beta }^{2}}}{{{b}^{2}}}=2$ C)  $\frac{{{a}^{2}}}{{{\alpha }^{2}}}-\frac{{{b}^{2}}}{{{\beta }^{2}}}=2$                        D)  All the above E)  None of these

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