question_answer

If for an isosceles triangles the length of each equal side is 'a' units and that of the third side is 'b' units, then its area will be

A)  \[\frac{a}{2}\,\sqrt{2{{a}^{2}}\,-\,{{b}^{2}}}\] sq. units

B)  \[\frac{b}{2}\,\sqrt{{{a}^{2}}\,-\,2{{b}^{2}}}\] sq. units

C)  \[\frac{a}{4}\,\sqrt{4{{a}^{2}}\,-\,{{b}^{2}}}\] sq. units

D)  \[\frac{b}{4}\,\sqrt{4{{a}^{2}}\,-\,{{b}^{2}}}\] sq. units

E)  None of these