I. \[16{{x}^{2}}-112x+75=0\] |
II. \[16{{y}^{2}}-96y-25=0\] |
A) \[x<y\]
B) \[x\ge y\]
C) \[x>y\]
D) \[x\le y\]
E) None of these
Correct Answer: B
Solution :
Not AvailableYou need to login to perform this action.
You will be redirected in
3 sec