A) 534
B) 754
C) 705
D) 684
Correct Answer: D
Solution :
[d] Let ABCD is the plot with sides shown. Join AC As \[\angle ABD=90{}^\circ \] \[\therefore \] \[AC=\sqrt{A{{B}^{2}}+B{{C}^{2}}}=\sqrt{{{32}^{2}}+{{24}^{2}}}\] AC = 40 m Area of \[\Delta ABC\text{=}\frac{1}{2}\times 32\times 24\,\] \[Area\,o\text{f}\,\Delta \text{ABC=384}\,{{\text{m}}^{\text{2}}}\] ? (1) \[Area\,o\text{f}\,\Delta \text{ACD=}\sqrt{s(s-AC)(s-CD)(s-AD)}\] S = semi perimeter of \[\Delta \text{ACD}\] \[s=\frac{25+25+40}{2}=45\] \[\therefore \,\,\,Area\,\,o\text{f}\,\Delta \text{ACD}\] \[=\sqrt{45(45-40)(45-25)(45-25)}=300{{m}^{2}}\] Area of plot ABCD = Area of \[\Delta \text{ABC}\] + Area of \[\Delta \text{ACD}\] \[=384+300=684{{m}^{2}}\]You need to login to perform this action.
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