A) \[120{}^\circ \]
B) \[150{}^\circ \]
C) \[30{}^\circ \]
D) \[60{}^\circ \]
Correct Answer: B
Solution :
Given equation, \[x+\sqrt{3}y-6=0\] \[\sqrt{3}y=-x+6\] \[y=\frac{-x}{\sqrt{3}}+\frac{6}{\sqrt{3}}\] \[M=\tan \theta =-\frac{1}{\sqrt{3}}\] \[=-\tan 30{}^\circ =\tan \,\,(180{}^\circ -30{}^\circ )=\tan 150{}^\circ \]You need to login to perform this action.
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