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SSC Sample Paper Mock Test-1 SSC CGL Tear-II Paper-1

  • question_answer
    The angle made by the line \[x+\sqrt{3y}-6=0,\] positive direction of x-axis is                 

    A)  \[120{}^\circ \]           

    B)  \[150{}^\circ \]

    C)  \[30{}^\circ \]                         

    D)  \[60{}^\circ \]

    Correct Answer: B

    Solution :

    Given equation, \[x+\sqrt{3}y-6=0\] \[\sqrt{3}y=-x+6\] \[y=\frac{-x}{\sqrt{3}}+\frac{6}{\sqrt{3}}\] \[M=\tan \theta =-\frac{1}{\sqrt{3}}\] \[=-\tan 30{}^\circ =\tan \,\,(180{}^\circ -30{}^\circ )=\tan 150{}^\circ \]


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