A) 1760 cu cm
B) 880 cu cm
C) 440 cu cm
D) 220 cu cm
Correct Answer: C
Solution :
The volume of iron used \[=\pi r_{1}^{2}h-\pi r_{2}^{2}h=\pi h\,\,(r_{1}^{2}-r_{2}^{2})\] \[=\frac{22}{7}\times 20\,\,({{4}^{2}}-{{3}^{2}})=\frac{22}{7}\times 20\times 7=440\,\,\text{cu}\,\,\text{cm}\]You need to login to perform this action.
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