A) \[3x-y=9\]
B) \[x+5y=-10\]
C) \[x+4y=10\]
D) \[x-4y=10\]
Correct Answer: B
Solution :
Let the equation of line be x/a +y/ b= 1 |
AB is perpendicular to y = 5x |
Hence, |
\[-b/a\times 5=-1\]\[\Rightarrow \]\[5b=a\] |
Area of \[\Delta OAB=\frac{1}{2}\left| ab \right|\] |
\[\Rightarrow \] \[10=\frac{1}{2}\left| 5{{b}^{2}} \right|\] |
\[\Rightarrow \] \[{{b}^{2}}=4\] |
\[\Rightarrow \] \[b=\pm 2,a\] |
\[=\pm 10\] |
The line can be \[x/10+y/2=1\]or |
\[x/10+y/2=-1\] |
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