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SSC Sample Paper Mock Test-13 SSC CGL Tear-II Paper-1

  • question_answer
    The smallest number, which, when divided by 12 or 10 or 8, leaves remainder 6 in each case, is

    A) 246

    B)  186    

    C)  126

    D)  66

    Correct Answer: C

    Solution :

    The smallest number divisible by 12 or 10 or 8 = LCM of 12, 10 and 8 = 120 \[\Rightarrow \]Required number \[=120+6=126\]


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