A) 100%
B) 200%
C) 300%
D) 400%
Correct Answer: C
Solution :
Let diameter = 2r \[\therefore \] Area \[=\pi {{r}^{2}}\] New diameter = 4r New area \[=4\pi {{r}^{2}}\] \[\therefore \] Increase in area \[=4\pi {{r}^{2}}-\pi {{r}^{2}}=3\pi {{r}^{2}}\] \[\therefore \] Increase percentage in area \[=\left( \frac{3\pi {{r}^{2}}}{\pi {{r}^{2}}}\times 100 \right)%=300%\]
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