A) 1
B) 4
C) 19
D) 41
Correct Answer: D
Solution :
1 man's 1 day's work \[=\frac{1}{3}\] |
1 woman's 1 day's work \[=\frac{1}{4}\] |
1 boy's 1 day's work \[=\frac{1}{2}\] |
(1 man + 1 woman)'s \[\frac{1}{4}\]day's work |
\[=\frac{1}{4}\left( \frac{1}{3}+\frac{1}{4} \right)=\frac{7}{48}\] |
Remaining work \[=1-\frac{7}{48}=\frac{41}{48}\] |
Mow, boy's \[\frac{1}{4}\] day's work \[=\frac{1}{48}\] |
\[\therefore \] \[\frac{41}{48}\]part work will be done by |
\[\frac{41}{48}\times 48=41\,\,\text{boys}\] |
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