A) 5000
B) 4950
C) 4980
D) 4900
Correct Answer: B
Solution :
Numbers divisible by 3 and lying between 100 and 200 are: 102, 105,..., 198 Let number of terms = n \[\therefore \] \[198=102+\,\,(n-1)\,\,3\] \[\Rightarrow \] \[n-1=\frac{198-102}{3}=32\]\[\Rightarrow \]\[n=33\] \[\therefore \] \[S=\frac{n}{2}\,\,(a+l)=\frac{33}{2}\,\,(102+198)=4950\]You need to login to perform this action.
You will be redirected in
3 sec