A) 12
B) 3
C) \[-\,\,1\]
D) 1
Correct Answer: D
Solution :
\[{{(a-1)}^{2}}+{{(b+2)}^{2}}+{{(c+1)}^{2}}=0\] \[\Rightarrow \] \[a-1=0\]\[\Rightarrow \]\[a=1;\] \[b+2=0\]\[\Rightarrow \]\[b=-2\] \[c+1=0\]\[\Rightarrow \]\[c=-1\] \[\therefore \] \[2a-3b+7c\] \[=2-3\,\,(-2)+7\,\,(-1)=2+6-7=1\]You need to login to perform this action.
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