A) 9, 4, 5
B) 3, 8, 2
C) 5, 3, 4
D) 3, 6, 2
Correct Answer: D
Solution :
\[{{a}^{2}}+{{b}^{2}}=45\] and \[{{b}^{2}}+{{c}^{2}}=40\] On subtracting, we get \[{{a}^{2}}-{{c}^{2}}=5\]\[\Rightarrow \]\[(a+c)(a-c)=5\] \[\Rightarrow \] \[a+c=5\] and \[a-c=1\] \[\Rightarrow \] \[a=3,\]\[c=2,\]\[9+{{b}^{2}}=45\]\[\Rightarrow \]\[{{b}^{2}}=36\] \[\Rightarrow \] \[b=\sqrt{36}=6\] \[\therefore \] \[a=3,\]\[b=6\]and \[c=2\]
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