A) \[4\frac{1}{2}%\]
B) \[4\frac{1}{5}%\]
C) \[4\frac{1}{6}%\]
D) \[4\frac{1}{3}%\]
Correct Answer: C
Solution :
| Let the rate per cent per annum be r. |
| Then \[2500=2304{{\left( 1+\frac{r}{100} \right)}^{2}}\] |
| \[\Rightarrow \] \[{{\left( 1+\frac{r}{100} \right)}^{2}}=\frac{2500}{2304}={{\left( \frac{50}{48} \right)}^{2}}\] |
| \[\Rightarrow \] \[1+\frac{r}{100}=\frac{50}{48}=\frac{25}{24}\] |
| \[\Rightarrow \] \[\frac{r}{100}=\frac{25}{24}-1=\frac{1}{24}\]\[\Rightarrow \]\[r=\frac{100}{24}\] |
| \[\Rightarrow \] \[r=\frac{25}{6}\]\[\Rightarrow \]\[r=4\frac{1}{6}%\] |
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