A) 1 : 1
B) 1 : 2
C) 1: 3
D) 2 : 3
Correct Answer: D
Solution :
As volumes are equal \[\Rightarrow \] \[\pi {{R}^{2}}H=\frac{4}{3}\pi {{R}^{3}}\]\[\Rightarrow \]\[\frac{H}{R}=\frac{4}{3}\] Ratio of the curved surface areas\[=\frac{2\pi RH}{4\pi {{R}^{2}}}=\frac{1}{2}\cdot \frac{H}{R}\] \[=\frac{1}{2}\times \frac{4}{3}=\frac{2}{3},\]\[\Rightarrow \]\[2:3\]
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