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SSC Sample Paper Mock Test-18 SSC CGL Tear-II Paper-1

  • question_answer
    If m and n are two integers such that\[m={{n}^{2}}-n,\]then\[({{m}^{2}}-2m)\]is always divisible by

    A) 9

    B)  16      

    C)  24

    D)  48

    Correct Answer: C

    Solution :

    Given, \[m={{n}^{2}}-n\] \[\therefore \]\[{{m}^{2}}-2m=\,\,{{({{n}^{2}}-n)}^{2}}-2({{n}^{2}}-n)\] \[=n\,\,(n-1)({{n}^{2}}-n-2)=(n+1)n\,\,(n-1)(n-2)\] It is product of consecutive number Hence, it is divisible by\[24\,\,({{4}^{1}}).\]


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