SSC Sample Paper Mock Test-2 SSC CGL Tear-II Paper-1

  • question_answer
             Two numbers have 16 as their HCF and 146 as their LCM. How many such pairs of numbers are there?

    A)  Zero    

    B)                     Only 1

    C)  Only 2 

    D)         Many 

    Correct Answer: A

    Solution :

    HCF of two numbers = 16 and LCM of two number = 146 Let the first number, y =16 a and the second number, y = 16 b We know that, HCF \[\times \]LCM= product of two numbers \[\Rightarrow \]\[16\times 146=x\times y\]\[\Rightarrow \]\[16\times 146=16a\times 16b\] \[\Rightarrow \]   \[a\times b=\frac{146}{16}=9.125\] The number of such pairs is zero, since \[a\times b\]is not integer.


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