A) \[1\frac{1}{6}\]
B) \[\frac{6}{7}\]
C) 1
D) None of these
Correct Answer: B
Solution :
| Let \[\frac{5}{6}\div \frac{6}{7}\times x-\frac{8}{9}\div \frac{8}{5}+\frac{3}{4}\times \frac{10}{3}=\frac{25}{9}\] |
| Then,\[\frac{5}{6}\times \frac{7}{6}\times x-\frac{8}{9}\times \frac{5}{8}+\frac{3}{4}\times \frac{10}{3}=\frac{25}{9}\] |
| \[\Rightarrow \] \[\frac{35}{36}\times -\frac{5}{9}+\frac{5}{2}=\frac{25}{9}\] |
| \[\Rightarrow \] \[\frac{35}{36}x=\frac{25}{9}+\frac{5}{9}-\frac{5}{2}=\frac{30}{9}-\frac{5}{2}\] |
| \[\Rightarrow \] \[\frac{35}{36}\times =\frac{10}{3}-\frac{5}{2}=\frac{5}{6}\] |
| \[\Rightarrow \] \[x=\left( \frac{5}{6}\times \frac{36}{35} \right)=\frac{6}{7}\] |
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