A) 22.31 m
B) 22.56 m
C) 20 m
D) 19.5 m
Correct Answer: B
Solution :
Given that, Length of a box (l) = 14 m Breadth of a box = 12 m and height of a box (h) = 13 m \[\therefore \]The length of the greatest rod that can be put in box = Length of the diagonal of a box \[=\sqrt{{{l}^{2}}+{{b}^{2}}+{{h}^{2}}}=\sqrt{{{(14)}^{2}}+{{(12)}^{2}}+{{(13)}^{2}}}\] \[=\sqrt{196+144+169}\] \[=\sqrt{509}=22.56\,\,m\]
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