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SSC Sample Paper Mock Test-20 SSC CGL Tear-II Paper-1

  • question_answer
    \[\left( 1-\frac{1}{3} \right)\left( 1-\frac{1}{4} \right)\left( 1-\frac{1}{5} \right)...\left( 1-\frac{1}{99} \right)\left( 1-\frac{1}{100} \right)\]is equal to

    A)  \[\frac{1}{50}\]

    B)  \[\frac{1}{45}\]

    C)  \[\frac{1}{100}\]          

    D)  \[0\]

    Correct Answer: A

    Solution :

    Given expression \[=\frac{2}{3}\times \frac{3}{4}\times \frac{4}{5}\times ...\times \frac{98}{99}\times \frac{99}{100}=\frac{2}{100}=\frac{1}{50}\]


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