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SSC Sample Paper Mock Test-20 SSC CGL Tear-II Paper-1

  • question_answer
    A circular wire of radius 42 cm is bent in the form of a rectangle whose sides are in the ratio of 6 : 5. The smaller side of the rectangle is \[\left( \text{Take}\,\,\pi =\frac{22}{7} \right)\]

    A) 60 cm

    B)  30 cm         

    C)  25 cm

    D)  36 cm  

    Correct Answer: A

    Solution :

    Circumference of the circular wire \[=2\pi r\]\[=2\times \frac{22}{7}\times 42=264\,\,\text{cm}\] Perimeter of rectangle \[=264\,\,\text{cm}\] Let the sides of rectangle be \[6x\,\,\text{cm}\]and \[5x\,\,\text{cm}.\] \[\therefore \]      \[2\,(6x+5x)=264\] \[\Rightarrow \]   \[2\times 11x=264\] \[\Rightarrow \]   \[x=\frac{264}{22}=12\] \[\therefore \] The smaller, side \[=5x=5\times 12=60\,\,\text{cm}\]


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