A) \[50{}^\circ \]
B) \[80{}^\circ \]
C) \[75{}^\circ \]
D) \[65{}^\circ \]
Correct Answer: A
Solution :
Draw, AB || PQ \[\angle ATP=\angle TPQ=50{}^\circ \]and\[\angle BTR+\angle TRS=180{}^\circ \] \[\angle BTR=80{}^\circ \] and \[\angle ATP+x+\angle BTR=180{}^\circ \] \[\therefore \] \[x=180{}^\circ -\,\,(50{}^\circ +80{}^\circ )=50{}^\circ \]You need to login to perform this action.
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