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SSC Sample Paper Mock Test-3 SSC CGL Tear-II Paper-1

  • question_answer
    The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is

    A)  9 cm                           

    B)  18 cm

    C)  8 cm                           

    D)  12.5 cm

    Correct Answer: B

    Solution :

    Area of the first triangle \[=\frac{1}{2}\times \]Base \[\times \]Height \[=\frac{1}{2}\times 15\times 12=90\,\,c{{m}^{2}}\] According to the question,                     Area of the another (second) triangle \[=2\times 90=180\,\,c{{m}^{2}}\] Area of the new triangle \[180\,\,c{{m}^{2}}=\frac{1}{2}\times 20\times \text{Height}\] \[\therefore \]      Height \[=\frac{180\times 2}{20}=18\,\,cm\]


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