SSC Sample Paper Mock Test-3 SSC CGL Tear-II Paper-1

  • question_answer
    The perimeter of two squares are 24 cm and 32 cm. The perimeter (in cm) of a third square equal in area to the sum of the areas of these squares is

    A)  45                               

    B)  40

    C)  32                               

    D)  48

    Correct Answer: B

    Solution :

    Side of square, whose perimeter is \[24\,\text{cm}=\frac{24}{4}=6\,\text{cm}\] \[\therefore \]Area of the square \[={{6}^{2}}=36\,\,\text{c}{{\text{m}}^{2}}\] Again, side of square, whose perimeter is 32 cm \[=\frac{32}{4}=8\,\,\text{cm}\] \[\therefore \]Area of the square \[={{8}^{2}}=64\,\,\text{c}{{\text{m}}^{2}}\] According to the question, Area of the new square \[=64+36=100\,\,\text{c}{{\text{m}}^{2}}\] \[\therefore \]Side of the new square \[=\sqrt{100}=10\,\,\text{cm}\] \[\therefore \]Perimeter of the new square \[=10\times 4=40\,\,\text{cm}\]


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