A) 0.28
B) 1.1
C) 11
D) 2.8
Correct Answer: B
Solution :
Let 0.41 = x and 0.69= y \[\therefore \] Expression \[=\frac{({{x}^{3}}+{{y}^{3}})}{({{x}^{2}}-xy+{{y}^{2}})}\] \[=\frac{(x+y)({{x}^{2}}-xy+{{y}^{2}})}{({{x}^{2}}-xy+{{y}^{2}})}\] \[=x+y=0.41+-.0690=1.10\]You need to login to perform this action.
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