A) (a) Rs. 6500
B) Rs.5500
C) (b) Rs. 6000
D) Rs.7000
Correct Answer: C
Solution :
Let the sum be Rs. x. Then, \[CI=x{{\left( 1+\frac{5}{100} \right)}^{2}}-x\] \[=\frac{441x}{400}-x=\frac{441x-400x}{400}=\frac{41}{400}x\] \[SI=\frac{x\times 5\times 2}{100}=\frac{x}{10}\] \[\therefore \]\[(CI)-(SI)=\frac{41x}{400}-\frac{x}{10}=\frac{41x-40x}{400}=\frac{x}{400}\] \[\therefore \] \[\frac{x}{400}=15\] \[\Rightarrow \] \[x=15\times 400=6000\] Hence, the sum is Rs.6000You need to login to perform this action.
You will be redirected in
3 sec