A) \[8000\,\,c{{m}^{3}}\]
B) \[8100\,\,c{{m}^{3}}\]
C) \[8171.43\,\,c{{m}^{3}}\]
D) \[8200.43\,\,c{{m}^{3}}\]
Correct Answer: C
Solution :
Capacity of bucket = Volume of frustum of a cone \[=\frac{\pi h}{3}[{{R}^{2}}+{{r}^{2}}+\operatorname{Rr}]=\frac{22}{7}\times \frac{24}{3}[{{(15)}^{2}}+{{5}^{2}}+15\times 5]\,\,c{{m}^{2}}\]\[=\frac{22}{7}\times 8\,\,[225+25+75]\,\,c{{m}^{3}}=\frac{176}{7}(325)\,\,c{{m}^{3}}\] \[=817143.\,\,c{{m}^{3}}\]You need to login to perform this action.
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