A) 1
B) 2
C) 3
D) 0
Correct Answer: B
Solution :
HCF of two number = 27 \[\therefore \]Let the numbers be 27 x and 27 y where x and y are prime to each other. According to the question, \[27x+27y=216\]g \[\Rightarrow \] \[27\,\,(x+y)=216\] \[\therefore \] \[(x+y)=\frac{216}{27}=8\] \[\therefore \] Possible pairs of x and y = (1, 7) and (3, 6) \[\therefore \] Number = (27, 189) and (81, 135)You need to login to perform this action.
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