A) \[x=1\]
B) \[x=2\]
C) \[x=\frac{1}{2}\]
D) \[x=\frac{3}{2}\]
Correct Answer: A
Solution :
Given, \[\frac{x\cdot \text{cose}{{\text{c}}^{2}}30{}^\circ {{\sec }^{2}}45{}^\circ }{8{{\cos }^{2}}45{}^\circ {{\sin }^{2}}60{}^\circ }\] \[=-{{\tan }^{2}}60{}^\circ -{{\tan }^{2}}30{}^\circ \] \[\Rightarrow \]\[\frac{x\times {{(2)}^{2}}\times {{(\sqrt{2})}^{2}}}{8\times {{\left( \frac{1}{\sqrt{2}} \right)}^{2}}\times {{\left( \frac{\sqrt{3}}{2} \right)}^{2}}}=({{\sqrt{3}}^{2}})-{{\left( \frac{1}{\sqrt{3}} \right)}^{2}}\] \[\Rightarrow \] \[\frac{x\times 4\times 2\times 4}{8\times \frac{1}{2}\times 3}=3-\frac{1}{3}\]\[\Rightarrow \]\[\frac{8x}{3}=\frac{8}{3}\] \[\Rightarrow \] \[x=1\]You need to login to perform this action.
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