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SSC Sample Paper Mock Test-7 SSC CGL Tear-II Paper-1

  • question_answer
    Check, if \[x-3\] is a factor of\[{{x}^{3}}+{{x}^{2}}-17x+15,\] then the value of remainder is

    A)  0

    B)  1         

    C)  2

    D)  4

    Correct Answer: A

    Solution :

    Here, \[p\,\,(x)={{x}^{3}}+{{x}^{2}}-17x+15\] and, \[(x-3)\] will be a factor of  p(x), if p(3) = 0 So,\[p\,\,(3)={{(3)}^{3}}+{{(3)}^{2}}-17\times 3+15\] \[=27+9-51+15=51-51=0\]         \[\therefore \]      \[x-3\] is a factor of p(x).


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