A) Rs. 3500, Rs. 5500
B) Rs. 4500, Rs. 4500
C) Rs. 4000, Rs. 5000
D) Rs. 5300, Rs. 3700
Correct Answer: C
Solution :
Let cost price of one scooter = Rs. xCost price of other scooter = Rs. \[(900-x)\] |
\[\therefore \]Selling price of first scooter \[=x+\frac{25x}{100}=\frac{125x}{100}\] |
Also, selling price of second scooter |
\[=(9000-x)\left( 1-\frac{20}{100} \right)=(9000-x)\left( \frac{80}{100} \right)\] |
\[\therefore \]Total selling price of scooter |
\[=\frac{125x}{100}+(9000-x)\frac{80}{100}\] |
\[\therefore \] \[\frac{125x}{100}+(9000-x)\frac{80}{100}=9000\] (given) |
\[\frac{45x}{100}+7200=9000\] |
\[45x=180000\] |
\[=\frac{1}{3}\times \pi \times \frac{9}{2}\times \frac{9}{2}\times 9=\frac{2673}{14}c{{m}^{3}}\]= Rs. 4000 |
\[\therefore \] Cost price of 1st scooter = Rs. 4000 |
Cost price of 2nd scooter = Rs. 5000 |
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