A) 1
B) 0.1
C) 0.01
D) 0.001
Correct Answer: C
Solution :
Using the formula \[{{a}^{3}}-{{b}^{3}}=(a-b)({{a}^{2}}+ab+{{b}^{2}})\] |
\[?=\frac{0.05\times 0.05\times 0.05-0.04\times 0.04\times 0.04}{0.05\times 0.05+0.002+0.04\times 0.04}\] |
\[=\frac{{{(0.05)}^{3}}-{{(0.04)}^{3}}}{{{(0.05)}^{2}}+0.05\times 0.04+{{(0.04)}^{2}}}\] |
\[=0.05-0.04=0.01\] |
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