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SSC Sample Paper Mock Test-9 SSC CGL Tear-II Paper-1

  • question_answer
    If \[{{(102)}^{2}}=10404,\] then the value of\[\sqrt{104.04}+\sqrt{1.0404}+\sqrt{0.010404}\] is equal to

    A) 0.306

    B)  0.0306

    C)  11.122

    D)  11.322

    Correct Answer: D

    Solution :

    \[\therefore \]\[{{(102)}^{2}}=10404\] \[\Rightarrow \]\[\sqrt{10404}=102=\sqrt{104.04}+\sqrt{1.0404}+\sqrt{0.010404}\]            \[=10.2+1.02+0.102=11.322\]


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