A) 9
B) 7
C) 8
D) 6
Correct Answer: B
Solution :
Let the numbers be x and y. \[xy=120\] \[{{x}^{2}}+{{y}^{2}}=289\] \[{{(x-y)}^{2}}={{x}^{2}}+{{y}^{2}}-2xy\] \[=289-2x\times 120\] \[=289-240=49\] \[\therefore \] \[x-y=7\]You need to login to perform this action.
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